Math, asked by 35597, 1 year ago

find the area of the rectangle of length(3x-2) and beradth(7x-3)

bhumi51: please give me the answer of this question ...

bhumi51: a(a+b)power 3- 3a^b(a+b)

Answers

Answered by dikshachoudary

[3x-2][7x-3]
3x[7x-3]-2[7x-3]
21x^2 - 9x - 14x +6
21x^2 - 23x +6
Now solve this quadratic equation

bhumi51: I need one help

dikshachoudary: What

bhumi51: abcd is a parallelogram and ,y are mid points...of an and CD respectively.prove that acxy is a parallelogram ...

bhumi51: x and y are mid points on ab and CD respectively..

bhumi51: can u tell me this???

dikshachoudary: We have given that AB is parallel to CD and x and y are the mid point of AB and CD. So, AX is also parallel to CY.

dikshachoudary: And we know that if one side of a parallelogram are equal and parallel then the other side are also equal and parallel. Hence AXCY is a parallelogram

dikshachoudary: I hope u understand

bhumi51: thanks so much

dikshachoudary: You're welcome

Answered by BloomingBud

Hi !!!!!!

Here is your answer,

Given:- length of rectangle = (3x-2)
breadth = (7x-3)

$area \: \: of \: \: rectangle = length \times breath \\ \\ = (3x - 2) \times (7x - 3) \\ \\ = 3x(7x - 3) - 2(7x - 3) \\ \\ = 3x \times 7x + 3x \times ( - 3) - 2 \times 7x - 2 \times ( - 3) \\ \\ = 21 {x}^{2} - 9x - 14x + 6 \\ \\ = 21 {x}^{2} - 23x +6$

Hope it helps !!!!!!

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