Math, asked by ayush1424, 9 months ago

Find the area of the rectangle whose breadth is one-third of its length and whose perimeter is same as
that of the perimeter of the square of area 256 sq cm.
plese give solution step by step

Answers

Answered by ganeshbhatk
2

Answer:

Step-by-step explanation:

area of the rectangle =l x b

Answered by manmaththote2009
1

Answer:

84.8

Step-by-step explanation:

A=l×b

Sq of 256 is 16

1\3 is 5.3

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