Question

Find the area of the rectangle whose length and breadths are 3x^2y m and 5xy^2 m respectively. * ​

Answer 1

Step-by-step explanation:

Area of rectangle = length (l)*breadth(b)

Area of rectangle= (3x^2y)*(5xy^2)

Area of rectangle=(15x^2y + 1)*y^2

Therefore, Area of rectangle =

${15}^{2y + 1} {y}^{2} ....ans$

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Answer 2

Given,

Dimensions of a rectangle;

Length= L = 3x^2y meters

Breadth= B = 5xy^2 meters

To find,

The area of the rectangle.

Solution,

We can simply solve this mathematical problem using the following process:

As per the concepts of mensuration,

Area of a rectangle

= Area (rectangle) = Length X breadth

Now,

area of the given rectangle

= Length X breadth

= L X B

= (3x^2y meters) X (5xy^2 meters)

= 15(xy)^3 square meters

Hence, the area of the rectangle is 15(xy)^3 square meters.