find the area of the rectangle whose length and breath are y+4 and y-3
Answers
Answered by
0
Answer:
y square+y-12
Step-by-step explanation:
{y+4}{y-3}
=y square + y - 12
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Answered by
1
Answer:
l=7
b=0
Step-by-step explanation:
l=y+4
b=y-3
area of rectangle=l×b
=(y+4) (y-3) =0
=y^+y-12=0
=y^+4y-3y-12=0
=y(y+4) -3(y+4)=0
=(y-3)(y+4)=0
=y=3 or y=-4
therefore, y= 3.
l=y+4
l =3+4
l =7
b= y-3
b =3-3
b =0
therefore area of rectangle=l×b
=7×0
=0
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