Question

find the area of the rectangle whose length is 20 cm and breadth is equal to the perimeter of a square whose area is 9 CM²​

Answer 1

Answer:

240 sq.cm

Step-by-step explanation:

please mark me as brainliest

Answer 2

Given :-

• Length of Rectangle = 20cm
• Breadth of Rectangle is equal to the perimeter of a square whose area is 9cm²

To Find :-

• The Area of Rectangle.

Solution :-

➞ Area of Square = Side × Side

➞ Area of Square = (Side)²

➞ 9 = (Side)²

➞ √9 = Side

➞ 3cm = Side

________________

➞ Perimeter of Square = 4 × Side

➞ Perimeter of Square = 4 × 3

➞ Perimeter of Square = 12cm

________________

It is given that Breadth of the Rectangle = Perimeter of the Square, so Breadth of the Rectangle is 12cm

➞ Area of Rectangle = Length × Breadth

➞ Area of Rectangle = 12 × 20

➞ Area of Rectangle = 240cm²

________________

Therefore, The Area of Rectangle is 240cm²

________________

★ Additional Info :

Formulas Related to Rectangle :

• Perimeter of Rectangle = 2( l + b)
• Area = Length × Breadth
• Length = Area / Breadth
• Breadth = Area / Length
• Diagonal = √(l)² + (b)²

Formulas Related to Square :

• Perimeter = 4 × Side
• Area = Side × Side
• Side of Square = √Area
• Diagonal = √2 × Side
• Area = ½ × (Diagonal)²
• Area = (Perimeter ÷ 4)²

________________