Physics, asked by venusking, 20 days ago

Find the area of the rectangle whose length is 5.5cm and breadth 4 cm ?!?????!?​

Answers

Answered by MoonlightPhoenix
4

Finding Area of Rectangle :

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

  • L = 5.5 cm

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

  • B = 4 cm

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

\pink\bigstarRequired Diagram :

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 5.5cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 4 cm}\put(-0.5,-0.4){\bf }\put(-0.5,3.2){\bf }\put(5.3,-0.4){\bf }\put(5.3,3.2){\bf }\end{picture}

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

Applying Formula :

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

  • L × B

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

• Putting Value :

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

  • L × B

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

  • 5.5 cm × 4 cm

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

  • A = 22 cm²

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

• Area of Rectangle = 22 cm²

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;

\red\bigstarNote :

  • Kindly view answer from brainly.in for clear view of diagram !

__________________________

Answered by llMissSwagll
45

\huge \sf{ \underline{ \pink{ \underline{ \blue{ \underline{ \pink{ \underline{ \blue{answer❤}}}}}}}}}

Finding Area of Rectangle :

L = 5.5 cm

B = 4 cm

\pink Required \:  Diagram :

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 5.5cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 4 cm}\put(-0.5,-0.4){\bf }\put(-0.5,3.2){\bf }\put(5.3,-0.4){\bf }\put(5.3,3.2){\bf }\end{picture}

❤Applying Formula :-

L × B

Putting Value :-

L × B

 \fbox \red{5.5 cm × 4 cm}

A = 22 cm²

  • ❤Area of Rectangle = 22 cm²

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