Math, asked by rohinidhataram, 11 months ago

find the area of the rectangle whose perimeter is 24 and breadth is 3​

Answers

Answered by Anonymous
1

perimeter=2(l+b)

24=2(x+3)

24/2=x+3

12-3=x

x=length=9

area = l*b

area = 9*3=27unit ^2

....

Answered by anoopsunny2003
0

Answer: 27

EXPLANATION:

Perimeter= 2 (l+b)

Let length be ' x '

24 = 2(x+3)

24/2 = x+3

12-3 = x

x = Length = 9

area = l*b

area = 9*3 = 27

Hope it helps :)

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