find the area of the rectangle whose perimeter is 320m
DIVYASHGUPTA:
what is the length or breadth
it must be given
it's rectangle or square
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The perimeter of rectangle =2 (l+b)
320/2 =l+b
160 =l+b
160-l = b
Area = lb
= l(160-l)
=160l-l^2 m^2
320/2 =l+b
160 =l+b
160-l = b
Area = lb
= l(160-l)
=160l-l^2 m^2
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