Question

Find the area of the region between two concentric circular path ,if the radius of the circular paths are 21m and 49m respectively​

Answer 1

Answer:

answer =616000m^2

Step-by-step explanation:

Area of the required region

= pie R^2- pie R^2

=pie (R^2-r^2)

=pie (R+r) (R-r)

= 22/7 ×(1190+210) (490 - 210)

= 22/7×700 ×280

=616000 m^2 .

Answer 2

Given,

Radius of concentric circular path,

$\[\begin{array}{l}R = 49m\\r = 21m\end{array}\]$

Solution,

Calculate the area of the region between two concentric circular path,

$\[\begin{array}{l} = \pi {R^2} - \pi {r^2}\\ = \pi \times {49^2} - \pi \times {21^2}\\ = \pi \times 2401 - \pi \times 441\\ = 1960\pi \\ = 6157.5216{m^2}\end{array}\]$

Hence the area of the region between concentric path is $\[6157.5216{m^2}\]$.