Question

find the area of the region bounded by curve y=2x and the line x=0 and y=1​

Answer 1

Answer:

The area of the region bounded by curve y=2x and the line x=0 and y=1​ is 4.

Step-by-step explanation:

Step 1: The difference between the areas beneath the two curves that form a boundary is the area between the curves. You will then have the area between the two curves, or the difference, between them.

Step 2: Integrate the difference of the functions to determine the area between two curves specified by functions. Use the absolute value of the difference between the functions if the graphs of the functions intersect or if the region is complicated.

Step 3: A territory is said to be bounded if it has a border or other restrictions applied to it. In other words, a bounded form is limited by a set of measurements or characteristics and cannot be an indefinitely huge area. On the Cartesian plane, a square has a natural border (four sides).

$\begin{aligned}& y=2 x_1 \quad x=2 \\& y=(2)(2)=4\end{aligned}$

$\text { Area } \Rightarrow \int_0^1 2 x d x$

$\left.\Rightarrow \quad 2 \frac{x^2}{z}\right|_0 ^2 \Rightarrow 2^2-0^2$

= 4-0=4

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Answer 2

Answer:

The area of the region bounded by curve y=2x and the line x=0 and y=1​ is 4 sq. units.

Step-by-step explanation:

Step 1: The difference between the areas beneath the two curves that form a boundary is the area between the curves. You will then have the area between the two curves, or the difference, between them.

Step 2: Integrate the difference of the functions to determine the area between two curves specified by functions. Use the absolute value of the difference between the functions if the graphs of the functions intersect or if the region is complicated.

Step 3: A territory is said to be bounded if it has a border or other restrictions applied to it. In other words, a bounded form is limited by a set of measurements or characteristics and cannot be an indefinitely huge area. On the Cartesian plane, a square has a natural border (four sides).

$y=2x_{1} \ x=2$

$y=2\times2=4$

$Area= \int\limits^0_1 {2x} \, dx$

$=2^{2} -0^{2}$

= 4-0=4

The area of the region bounded by curve y=2x and the line x=0 and y=1​ is 4 sq. units.

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