Question

Find the area of the region bounded by the curve y2 – 6y + x + 5 = 0 and y-axis.​

Answer 1

Answer:

${y}^{2} - 6y + x + 5 = 0 \\ {y}^{2} - 6y = - x - 5 \\ {y}^{2} - 6y + 9 = - x - 5 + 9 \\ {(y - 3)}^{2} = 4 - x \\ {(y - 3)}^{2} = - (x - 4)$

So its left handed parabola having vertex (4, 3).

Point of intersection with y axis

put x = 0.

${(y - 3)}^{2} = 4 \\ y - 3 = 2 \: or \: - 2 \\ y = 5 \: or \: 1$

Step-by-step explanation:

Answer is 10 square units

Answer 2

Answer:

answer is 10 square unit.........