Question

find the area of the region {(x,y)x²+y ⩽ 1 ⩽ x+y}​

Answer 1

Answer:

(1,0) and (0,1)

Step-by-step explanation:

x+y =1 .............(1)

x^2+y =1 ..........(2)

now

x^2+ y = 1 .........(2)

x + y = 1 ...........(1)

- - -

_______________________

x^2-x = 0

x(x-1) = 0

x = 0 and x-1 = 0 => x = 1

now values of x = 0 put in (1)

0+y = 1 => y = 1

and

values of x = 1 put in (2)

1+y = 1

y = 0

so (0,1) and (1,0) interval lay in 1st quardent.