Question

Find the area of the regular hexagon PQRSU in which each side measure 17 metre and its height is 33m

Answer 1

Answer:

The area is 841.5 m^2

Step-by-step explanation:

We can divide the hexagon into 6 ∆s.

These are all of equal dimensions.

So, ar(hexagon)=6*ar(∆)

ar(∆)=(height/2)*(1/2)*side

ar(∆)=(33/2)*(1/2)*17

ar(∆)=561/4

ar(hexagon)=561*6/4

ar(hexagon)=561*1.5

ar(hexagon)=841.5 m^2