Question

find the area of the regular octagen having each side equal to 5cm. HC = 11cm and AL=4 cm​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given that,

Side of the regulan octagen = 5 cm

Area of the ongular octagon

$\bf \: A = 2( \sqrt(2) + 1) \times (side) ^ 2 \\ \bf=2( \sqrt 2 +1)25 \\ \bf =2( \sqrt 2 +1(5)^ 2 \\ \bf =50( \sqrt 2 +1)cm^ 2 \: (ans)$