Find the area of the regular polygon with the given radius or apothem.
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Answer:
Given:
Apothem = 8√3
Solution:
In the, given attachment you can see that the apothem forms a right angled triangle with one of the sides of the hexagon.
The triangle so formed, is a triangle with 30°, 60°, and 90° which is a property of any right angled triangle in hexagon.
They are in proportion of x - x√3 - 2x, with x√3 being the apothem and x is the short leg.
Therefore,
x√3 = 8√3
=⟩ x = 8√3 / √3
= 8
Therefore, length of the short leg is 8in.
The short leg is half of the side of the hexagon.
Hence, side of the hexagon
= 2x
= 2 × 8
= 16in.
Now, perimeter of the hexagon
= 16 × 6
= 96in.
Now, knowing the perimeter (p) and the apothem (a) of the hexagon, the area of the hexagon can be calculated by the following formula:
Area = 1/2 × p × a
= 1/2 × 96 × 8√3
= 384√3 in²
[Note: You can also calculate the area directly by using the formula (3√3) / 2 × (side)², where you can input the side taken out previously.]
Hope you liked my answer, cheers :)
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