Question

find the area of the rhombus

Answer 1

Answer:

Let the length of other diagonal be a.

As we know diagonals of any rhombus bisect each other at 90°.

In any of the formed right angled triangle, applying Pythagoras theorem,

→ ( 1/2 of 6 )² + ( 1/2 of a )² = 5²

→ 3² + ( 1/2 of a )² = 5²

→ ( 1/2 of a )² = 5² - 3² = 25 - 9

→ ( 1/2 of a )² = 16

→ ( 1/2 of a ) = 4

We know,

Area of rhombus is half of the product of diagonals here,

Area = (1/2)(a)(6)

= 4*6

= 24 cm²

Hence, area of the rhombus is 24 cm².

Answer 2

Given:-

Length = 5 cm

diagonals = 6cm

To Find:-

Area of the rhombus

Calculations:-

Let the length of other diagonal be a. Diagonals of rhombus bisects each other at 90°.

NoW,

Applying Pythagoras formula,

➡ (1/2 of 6) ^2 +( 1/2 of a) ^2 = 5^2

➡ 3^2 +(1/2 of a^2) = 5^2

➡ (1/2 of a^2 ) = 5^2 - 3^2 = 25 - 9

➡ (1/2 of a^2) = 16

➡ (1/2 of a) = 4

We knoW,

Area of rhombus is half of the products of the diagonal ,here

Area = (1/2)(a)(6)

➡ 4*6

➡ ${\tt{24 cm^2}}$

${\tt {24 cm^2}}$will be the area of rhombus if the length of its side is 5 cm and it's diagonal will be 6 cm.