Question

Find the area of the rhombus

Answer 1

Area of the rhombus when 1 side and 1 diagonal is given= $\frac{1}{2}d\sqrt{4a^{2} - p^{2} }$

A= $\frac{1}{2} * 24 \sqrt{4*20^{2}- 24^{2} }$

A= $12\sqrt{1600-576}$

A=$12\sqrt{1024}$

A= $12*32$

Area= 384 cm²