Find the area of the rhombus ABCD, If AC = 6cm and BE = 4cm.
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Answered by
0
Answer:
Step-by-step explanation:
Diagnol 1 = 6cm
Diagnol 2= 8cm
Aream = DxD= 6x8=48cm2
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Answered by
2
Answer:
24cm^2
Step-by-step explanation:
The diagonal AC of the rhombus ABCD divides it into two triangles of equal areas
Now, area of triangle ABC = 1/ 2 ×base×height = 1/2 ×4×6=12cm^2
Therefore, area of the rhombus ABCD =2× Area of triangle ABC = 2×12 = 24cm^2
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