Question

Find the area of the rhombus ABCD, if its vertices taken in order are
A(2, -1), B(3, 4), C(-2, 3) and D(-3, -2).

Answer 1

Answer:

area of rhombus ABCD,

A = pq/2 (p, q are the diagnols)

p = AC = 4√2 = 5.657. q = BD = 3√13 = 10.82

A = 5.657(10.82)/2 = 61.20874/2 = 30.60 units ²