Question

find the area of the rhombus having diagonals equal to 6m and 8m​

Answer 1

Answer:

Using formula for area of quadilateral:

$\boxed{Area = \dfrac{1}{2} \times d_1 \times d_2}$

Here $d_1$ and $d_2$ are the diagonals

$\therefore Area = \dfrac{1}{2} \times 6 \times 8$

$\boxed{\implies{\boxed{Area = 24 \ m^2}}}$

Answer 2

Answer:

Hence, value of area of Rhombus will be 24 Sq. m

Step-by-step explanation:

In context to question asked,

We have to determine the area of rhombus.

As per data given in the question,

We have,

Diagonals of rhombus are 6 m and 8 m

As we know that,

Rhombus is a quadrilateral whose all sides are equal.

The sum of all the angles of the rhombus is 360 degree.

As we have,

Formula for finding the area of rhombus is $A = \frac{pq}{2}\\Where\:p\:and\:q \:are\:diagonals\:of\:Rhombus$

So, for determining the value of area of rhombus we will put the value of diagonals given in the question in above formula,

Thus we will get,

$A = \frac{pq}{2}\\=>A = \frac{6\times 8}{2} = \frac{48}{2} = 24\:m^2$