Find the area of the rhombus having each side equal to 15 cm and one of the diagonals is 24 cm.
Answers
Answered by
1
Answer:
180
Step-by-step explanation:
Area of rhombus =pq/2
15×24/2=180
Answered by
8
Solution ✌️
we know that the diagonals of a rhombus bisect each other at right angles.
so..OA=OC=AC/2
and. .OB=OD=BD/2=24/2=12cm
AB°BC=CD=DA=15cm
therefore...
So..
OA²=AB²-OB²
= >OA²=15²-12²=(15-12(15+12)
=>OA=√81=9
area of rhombus=4×area of ∆AOB
=4×(0.5×OA×OB)
=(2×9×12)cm²=216cm²
Area of the Rhombus=216cm²
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