Question

.Find the area of the rhombus of diagonals 15cm and 26 cm.​

Answer 1

Answer:

p2

a __

a

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Answer 2

Area of rhombus = product of diagonals /2

Area =15*26/2

Area =195cm²

The diagonals of rhombus bisects each other by 90°

Then by Pythagoras theorem,

(15/2)²+(26/2)²=side²

225/4 +169=side²

(225+679)/100=side²

904=100side²

904=(10side)²

√904 = 10side

√2 x 2 x 2 x 113 = 10side

4√226 = 10 side

side = 4√226/10 = 2√226/5

Perimeter = 4 x 2√226/5

Perimeter = 8√226/5 cm

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