Question

find the area of the rhombus of its vertices are (3,0) (4,5) (-1,4) (-2,-1). Taken in order

Answer 1

Answer:

SO GUYS, ITS OUR FIRST CBSE  BOARD EXAM.

SO, BEST OF LUCK DEARS .

NOW QUESTION

===> A(3,0) , B(4,5) , C(-1,4) , D(-2,-1)

ABCD IS A RHOMBUS

==> AREA OF RHOMBUS ==> 1/2 * AC * BD

==> DISTANCE B/W AC

==> AC² = (3+1)²+(0-4)²

==> AC² = 16 + 16

==> AC² = 32

==> AC = √32 ==> 4√2 UNIT

NOW, DISTANCE BETWEEN BD

==> BD² = (4+2)²+(5+1)²

==> BD² = 36+36

==> BD = √72

==> BD = 6√2 CM

AREA OF RHOMBUS ==> 1/2×AC×BD

==> 1/2×4√2×6√2

===> 2√2 × 6√2

==> 24 CM

AREA = 24 CM

Answer 2

Answer:

=> A(3,0) , B(4,5) , C(-1,4) , D(-2,-1)

ABCD IS A RHOMBUS

=> AREA OF RHOMBUS ==> 1/2 * AC * BD

=> DISTANCE B/W AC

=> AC² = (3+1)²+(0-4)²

=> AC² = 16 + 16

=> AC² = 32

=> AC = √32 ==> 4√2 UNIT

NOW, DISTANCE BETWEEN BD

=> BD² = (4+2)²+(5+1)²

=> BD² = 36+36

=> BD = √72

=> BD = 6√2 CM

AREA OF RHOMBUS ==> 1/2×AC×BD

=> 1/2×4√2×6√2

=> 2√2 × 6√2

=> 24 CM

AREA = 24 CM