Question

Find the area of the rhombus whose diagnols are 12 cm and 16.4 cm​

Answer 1

☆ Solution ☆

Given :-

• Diagonals of rhombus are 12 cm amd 16.4 cm

To Find :-

• The area of rhombus.

Step-by-Step-Explaination :-

As we know that :-

Area of Rhombus = 1/2 × D1 × D2

Where,

• D1 of the rhombus = 12 cm

• D2 of the rhombus = 16.4 cm

Putting the respective value,

Area of Rhombus = 1/2 × 12 × 16.4

Area of Rhombus = 1/2 × 196.8

Area of rhombus = 98.4

Hence,

The area of rhombus is 98.4 cm² .

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Know More :-

Perimeter of Rectangle = 2( L + B )

Perimeter of square = 4 × Side

Perimeter of triangle = AB + BC + CA

Area of Rectangle = L × B

Area of Square = ( side ) ²

Area of Rhombus = Product of Diagonal/2.

Area of Parallelogram = Base × Height.

Area of triangle = 1/2 × base × height .

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Answer 2

★ GiVeN ThaT :-

• $\sf{First \: Diagonal \: ( D_{1}) \: of \: Rhombus = 12 \: cm }$
• $\sf{Second \: Diagonal \: ( D_{2}) \: of \: Rhombus = 16.4 \: cm }$

★ To FinD :-

• Area of the Rhombus

★ FoRmuLaE usEd :-

$\large{\pink{\boxed{\sf{Area \: of \: the \: Rhombus = \frac{1}{2} \times D_{1} \times D_{2} \: {unit}^{2} }}}}$

★ SoLuTioN :-

$\large{\sf{Area \: of \: the \: Rhombus }}$

$\sf{ = \frac{1}{2} \times 12 \times 16.4 \: {cm}^{2} }$

$\sf{ = 6 \times 16.4 \: {cm}^{2} }$

$\sf\blue{\underline{ = 98.4 \: {cm}^{2} }}$

Hence, 98.4 cm² is the required Area of the Rhombus.