Question

find the area of the rhombus whose diagonals are 7 . 5 cm and 5 . 6 cm​

Answer 1

Answer:

=> The area of rhombus = $21cm^2$

Step-by-step explanation:

Given that:-

Diagonals of rhombus = $d_1=7.5cm$ and $d_2=5.6cm$

To find:-

The area of the rhombus = ?

As we know that,

The formula to be used for calculating the area of the rhombus,

$=> \frac{1}{2}\times [d_1 \times d_2]$

Now, plug all the values in the formula:

$=> \frac{1}{2}\times [7.5\times 5.6]$

=> $21cm^2$

Hence, the area of rhombus is $21cm^2$.

Answer 2

Given-

Diagonals are 7 . 5 cm and 5 . 6 cm​

To find-

The area of the rhombus

Solution -

Diagonals of Rhombus are indicated as d1 and d2

So,

d1 = $7.5cm$

d2 = $5.6cm$

The properties of Rhombus :-

• The opposite sides of a rhombus are parallel.
• All sides of the rhombus are equal.

As, we know that

Area of Rhombus = $\frac{1}{2}\times[d1 \times d2]$

Area of Rhombus = $\frac{1}{2}\times[7.5 \times 5.6]$

Area of Rhombus = $\frac{1}{2} \times 42$

Area of Rhombus = $21$ $cm^{2}$

∴ The Area of Rhombus is 21 $cm^{2}$