find the area of the Rhombus whose diagonals are the both 10 cm and 8.2 CM
Answers
Answered by
5
Area = pq/2
P and q are the diagonals
Therefore
Area = 41
P and q are the diagonals
Therefore
Area = 41
Answered by
4
Diagonals given= d1=10 cm
d2= 8.2 cm
Area of Rhombus = d1×d2÷2
10×8.2÷2=82÷2
=41 cm square
d2= 8.2 cm
Area of Rhombus = d1×d2÷2
10×8.2÷2=82÷2
=41 cm square
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