Question

Find the area of the rhombus whose perimeter is 80 m one of whose diagonal is 24 m.

Answer 1

side of rhombus is 80/4=20m ,now in triangle aob use Pythagoras theorem to calculate ob and thus to calculate another diagonal length.Now, the area of rhombus is 394m2...

Answer 2

Answer:

The area of the rhombus whose perimeter is 80 and diagonal 24m is $\bold{660 m^{2}}$.

Step-by-step explanation:

The formula for the exact perimeter of the “rhombus” is $\bold{2 \times \sqrt{d_{1}^{2}+d_{2}^{2}}}$

Let us take the diagonals as $d_{1} \text { and } d_{2}= d$ and 24 respectively

Now as written in the question the exact perimeter of the “rhombus” is 80m, therefore  

x$d_{1} \text { and } d_{2}= d$= 54.99=55 meter

Now as to find the total area of the “rhombus” we use the formula $\bold{\mathrm{A}=\frac{1}{2} d_{1} d_{2}}$

Hence the complete area of the “rhombus” is $A=\frac{1}{2}(24)(55)=660 m^{2}$.