Question

find the area of the Rhombus whose perimeter is 80 metre and one of whose diagonal is 24 metre​

Answer 1

Answer:

Perimeter of Rhombus = 80 m

Each side of rhombus measures 80/4 = 20 m

All the sides of rhombus are equal.

One diagonal of Rhombus measures 24 m

By using Pythagoras Theorem, we get

AB^2 + BC^2 = AC^2

or, 12^2 + BC^2 = 20^2

or, BC^2 = 400 - 144

or, BC = √256 = 16

The length of the other Diagonal is 2(16) = 32 m

Area of Rhombus = 1/2 × d1 × d2

Area of Rhombus = 1/2 × 24 × 32

Area of Rhombus = 12 × 32

Area of Rhombus = 384 sq.m

FOLLOW ME PLEASE.

Answer 2

Answer:

see this page for the answer .I hope I am right.