find the area of the rhombus whose side 5cm and altitude is 4.8cm. if one of its diagonals is in cm long find the length of the other diagonal
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use Pythagoras theorem.
H²= P² + B².
(5)² = (4.8)² + (B)².
25= 23.04 + B².
25-23.04 = B².
1.96 = B².
√1.96 = B
1.4 cm = B
the other diagonal is of 1.4 cm.
area of rhombus = 1/2 × ( d¹ × d²)
1/2 × (4.8 × 1.4)= 3.36
therefore, the area of the given rhombus is 3.36cm²
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