Question

find the area of the Rhombus whose side is 6 cm and altitude is 4 cm if one of its diagonal is 8 cm long find the other diagonal​

Answer 1

Answer:

Area of rhombus = 24 cm²

Length of the other diagonal = 6 cm.

Step-by-step explanation:

Given the side of the rhombus, b = 6 cm

Also, Given the altitude of rhombus , h = 4 cm,

Area of the rhombus when base(side) and altitude(h)

are given is given by A = base * height

Thus, Area of rhombus = 6 * 4  cm²

Area of rhombus = 24 cm².

Given one of the diagonal is of length  8 cm,

Let d₁ = 8 cm.

Let the length of the other diagonal be d₂.

If d₁, d₂ length of the diagonals are known, then

Area of rhombus is given by A = 1/2*d₁*d₂,

But we know, A = 24

Hence, 1/2*d₁*d₂ = 24

1/2*8*d₂ = 24

d₂ = 6 cm.

Hence, length of the other diagonal of rhombus

is 6 cm.

Hope, it helps !

Answer 2

Answer:

Step-by-step explanation:

SIDE IS 6CM

ALTITUDE IS 8CM

IN A RHOMBUS THE DIAGONAL BISECTS EACH OTHER AT 90 DEGREES, HALF OF DIAGONAL IS 8 DIVIDED BY 2 =4CM

H²=S²+S²

6²=4²+S²

S²=6²-4²

S²=36-16

S²=20

S=√20CM

OTHER DIAGONAL =2×√20

AREA OF RHOMBUS=1/2×D1D2

=1/2×8×2×√20

=8√20 CM²