Question

find the area of the Rhombus whose side is 6 cm and whose altitude is 4 cm if one of its diagonal is 8 cm long find the length of the Other diagonal​

Answer 1

Soln: Rhombus is also a kind of parallelogram
Therefore,
Area of rhom = base X altitude
=6x4
=24 cm sq
Also, area of rhombus = ½ × d1 × d2.....
24=1/2x8xd2
24= 4d2
d2= 24/4 = 6cm
Hence, the length of other diagonal is 6cm.


EXTRA
d1 - length of diagonal one,
d2 - length of diagonal two

Answer 2

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =6×4=24

Since, Area of rhombus is 24 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=8

Let length of other diagonal =$d_2$

After substituting the values, we get

$24=\frac{1}{2}×8×d_2$

$24=4×d_2$

$4×d_2=24$

$d_2=\frac{24}{4}$

$d_2=6$

Hence, length of other diagonal is 6 cm.