Find the area of the right angle triangle in which the hypotenuse is 26 cm and one of the adjacent side of right angle is 10 cm ans me..pls
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Answered by
4
Step-by-step explanation:
hypotenuse = 26 cm
one adjacent side = 10 cm
other one² = 26²-10²
=676 -100 = 576
another side = √576 =24 cm
area = ½*24*10
= 12*10 = 120 cm²
Answered by
76
Let triangle ABC is right angled at B.
AB2 + BC2 = AC2
According to the question,
AB = 10 cm and AC = 26 cm
102 + BC2 = 262
BC2 = 676 - 100
BC2 = 576
BC = 24 cm
Area of triangle = 1/2 * 10 * 24 = 120cm^2
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