Question

Find the area of the right-angled triangle ABC where CA = 16 cm, BC = 15 cm, ZBCA = 90°​

Answer 1

Answer:

Given :

In a right angled triangle ABC

CA = 16cm , BC = 15cm , angle BCA = 90degrees

Required to find :

1. Area of the triangle

Solution:

In the question it is given that In a right angled triangle ABC

angle c = 90degrees, CA = 16cm , BC = 15cm.

Using this hints we are going to draw the diagram of the right-angled triangle.

( please refer to the attachment it contains the diagram)

Before solving this question we should know what is the Formula of the area of the triangle.

Hence ,

Area of the triangle = 1/2 × base × height

Here ,

Base refers to the side which has height on it.

Height refers to the measurement of the perpendicular side which falls on the base.

Using this diagram we can find which is base and which is height.

Therefore from the diagram we concluded that .

Base = Side BC = 15cm.

Height = side CA = 16cm.

Hence by substituting this values in the formula we can know the area of the triangle.

Hence;

Area of the triangle =

$\frac{1}{2} \times 15 \times 16 \\ = 15 \times 8 \\ = 120 {cm}^{2}$

Therefore;

Area of the triangle = 120cm^2.