Find the area of the right angled triangle with hypotenuse 5cm and one of the acute angle is 48°30¹ (sin48°30¹=0.7490,cos48°30¹=0.6626
Answers
Answer:
Area of triangle = 6.2035 cm²
Step-by-step explanation:
sin x = opposite / hypotenuse
cos x = adjacent / hypotenuse
sin 48°30' = opposite / 5
0.7490 = opposite / 5
opposite = 5 × 0.7490 = 3.745 cm
cos 48°30' = adjacent / 5
0.6626 = adjacent / 5
adjacent = 0.6626 × 5 = 3.313 cm
Therefore, the height and base of the triangle is 3.745 cm and 3.313 cm.
Area of triangle = ½ × base × height
= ½ × 3.745 × 3.313
= 6.2035 cm²
Answer:
Find the area of the right angled triangle with hypotenuse 5 cm and one of acute angle is 48°38`.
__________________________
= sin θ =
= sin 48°20' =
= 0.7490 =
= 5 × 0.7490 = AB
= AB = 3.7450 cm.
____________________________
Then,
= cos θ =
= cos 48°30' =
= 0.6626 =
= 0.6626 × 5 = BC
= BC = 3.313 cm.
____________________________
Area of right triangle =
= × 3.3130 × 3.7450
= 1.6565 × 3.7450
= 6.2035925
_____________________
Step-by-step explanation:
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