Question

Find the area of the right triangle with the length of the hypotenuse of 7cm and the measure of 22.5 one angle of . Solve this task without using Trigonometry

Answer 1

Area of right angle triangle

$= \frac{1}{4} \times \: {hypotenuse}^{2}\times\: \sin(2\alpha )$

$= \frac{1}{4} \times \: {7}^{2}\times\: \sin(22.5 \degree )$

$= \frac{1}{4} \times 49 \times \sin \: 45 \degree$

$= \frac{49}{4} \sqrt{2}$

$= 8.66 \: {cm}^{2}$