Question

find the area of the rohmbus whose each side is 13m and one of the diognals is 10m.​

Answer 1

120m²

Answer:

area of rhombus = (product of diagonal) / 2

Step-by-step explanation:

The diagonals in a rhombus are perpendicular , and bisect each other

Given length of side is 13 cm and one diagonal as 10 cm we can find the length of other diagonal

From the above figure let DB be the 10 cm diagonal,now OB and OD are 5 cm

Now consider triangle AOB ,this is a right andled triangle and we know AB=10cm and OB=5cm ,using Pythagoras theorem we can find out lenth of OA as 12cm ,so length of diagonal AC is 2×12=24cm

Area of rhombus is product of diagonal divided by 2,

(24×10) ÷ 2 = 120 sq.cm

hope it will help you ❣️