Question

Find the area of the sector formed by the circle x^2 +y^2 =36 and the line
$y = \sqrt{3x}$

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Answer 1

Answer:

Area of the sector is 6π ≈ 18.857 units²

Step-by-step explanation:

x² + y² = 6² ( r = 6 )

y = x√3

x² + (x√3)² = 6²

x² + 3x² = 36

x² = 9

x = ± 3

$A_{circle}$ = πr² = 36π

Area of the sector = 36π ÷ 6 = 6π ≈ 18.857 units²