find the area of the sector of a circle of radius 10cm and of angle 60 degree. also find the area of the corresponding major sector
Answers
Answered by
4
Answer:
Step-by-step explanation:
Area of a sector =[ x/360] pi r^2
= [60/360] x 3.14 10 x10
= 314/6 = 52.3cm^2
Area of the cicle is 3.14 x 10 x 10 = 314
Hence area of the major sector = 314 - 52.3 = 261.7cm^2
Answered by
2
Answer:
Area of the minor sector = 52.4 cm²
Area of the major sector = 261.9 cm²
Step-by-step explanation:
Area of a sector = θ/360 x πr²
Find the area of the sector:
Area of the sector = 60/360 x π(10)² = 52.4 cm²
Find the area of the major sector:
Angle = 360 - 60 = 300º
Area of the sector = 300/360 x π(10)² = 261.9 cm²
Answer: Area of the minor sector = 52.4 cm² and the major sector is 261.9 cm²
Similar questions