Math, asked by zsparsh60, 1 year ago

find the area of the sector of a circle of radius 10cm and of angle 60 degree. also find the area of the corresponding major sector

Answers

Answered by sadikalisait
4

Answer:


Step-by-step explanation:

Area of a sector =[ x/360] pi r^2


= [60/360] x 3.14 10 x10


= 314/6 = 52.3cm^2


Area of the cicle is 3.14 x 10 x 10 = 314


Hence area of the major sector = 314 - 52.3 = 261.7cm^2

Answered by TooFree
2

Answer:

Area of the minor sector = 52.4 cm²

Area of the major sector = 261.9 cm²


Step-by-step explanation:

Area of a sector = θ/360 x πr²


Find the area of the sector:

Area of the sector = 60/360 x π(10)² = 52.4 cm²


Find the area of the major sector:

Angle = 360 - 60 = 300º

Area of the sector = 300/360  x π(10)² = 261.9 cm²


Answer: Area of the minor sector = 52.4 cm² and the major sector is 261.9 cm²

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