find the area of the sector of a circle whose radius is R and length of the arc is l
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Solution :
Given :
✏ Radius of Circle( Sector) = R
✏ Length of arc of Circle = l
To Find : Find the area of Sector ?
Solution :
Area of Sector = (Radius) × (Length of arc ) / 2
Area of Sector = R × l /2
_____________________________
Let the Length of arc is l and it's Radius is r
Area of Sector = πr²∅/360°
Hence, Required Formula of Area of Sector = 1/2 × (R) × (l) .
Given :
✏ Radius of Circle( Sector) = R
✏ Length of arc of Circle = l
To Find : Find the area of Sector ?
Solution :
Area of Sector = (Radius) × (Length of arc ) / 2
Area of Sector = R × l /2
_____________________________
Let the Length of arc is l and it's Radius is r
Area of Sector = πr²∅/360°
Hence, Required Formula of Area of Sector = 1/2 × (R) × (l) .
Answered by
3
SECTOR OF A CIRCLE:
The region enclosed by two radii and the corresponding arc of a circle is called the sector of a circle. The sector containing minor Arc is called minor sector and the sector containing major arc is called major sector. Angle of minor sector is less than 180° and Angle of major sector is more than 180°.The sum of angles of major and minor sector is 360°.
SOLUTION:
If the radius of a circle is r and length of the arc is l, then
Length of the arc (l) = (θ /360) ×2 πr……(1)
Length of the arc (l) = (θ /180) × πr
Area of sector = (θ /360) ×πr²
Area of sector = ½ ×r (θ / 180) ×πr
Area of sector =( ½) lr [ from eq 1]
Hence , the Area of sector = ( ½) lr sq units.
HOPE THIS WILL HELP YOU...
The region enclosed by two radii and the corresponding arc of a circle is called the sector of a circle. The sector containing minor Arc is called minor sector and the sector containing major arc is called major sector. Angle of minor sector is less than 180° and Angle of major sector is more than 180°.The sum of angles of major and minor sector is 360°.
SOLUTION:
If the radius of a circle is r and length of the arc is l, then
Length of the arc (l) = (θ /360) ×2 πr……(1)
Length of the arc (l) = (θ /180) × πr
Area of sector = (θ /360) ×πr²
Area of sector = ½ ×r (θ / 180) ×πr
Area of sector =( ½) lr [ from eq 1]
Hence , the Area of sector = ( ½) lr sq units.
HOPE THIS WILL HELP YOU...
divyanshGupta00:
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