Question

Find the area of the sector of a circle with radius 10 cm and central angle 60 degree. Also find the area of the corresponding major sector​

Answer 1

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Answer 2

Answer:

Area of sector = 52.34 $cm^{2}$

Area of major sector = 261.876 $cm^{2}$

Step-by-step explanation:

Area of sector = ∅/360° x π$r^{2}$

We have radius r =10 cm

Angle = 60°

Area of sector = $\frac{60}{360}$×$3.14$×$10$×$10$

                         =$\frac{1}{6}$×$314$

                        = $52.34 cm^{2}$

Area of major sector =( $360$°-∅)/360 x π$r^{2}$

                                   $\frac{360-60}{60} (3.14)( 10^{2} )\\\\= (300/360)(314)\\ =(0.834 )(314)\\ = 261.876 cm^{2}$