Question

find the area of the sector of a circle with radius 7cm and of angle 30°.also find the areas of the corresponding major sector.​

Answer 1

Step-by-step explanation:

area of sector = x/360 × π × r^2

$= \frac{30}{360} \times \frac{22}{7} \times {7}^{2} \\ = \frac{1}{12} \times 22 \times 7 \\ = \frac{11 \times 7}{6} \\ = \frac{77}{6} \\ = 12.83 \: {cm}^{2}$

area of major sector

$= \frac{330}{360} \times \frac{22}{7} \times {7}^{2} \\ = \frac{11 \times 22 \times 7}{12} \\ = \frac{11 \times 11 \times 7}{6} \\ = 141.16 \: {cm}^{2}$

hope you get your answer

Answer 2

Answer:

77/3 cm²

Step-by-step explanation:

Area of sector = Θ/360×πr²

                        = 60/360×22/7×7×7

                        = 1/6×22×7

                        = 1/3×11×7

                        = 77/3 cm²