find the area of the sector which ha radius 6cm and perimeter 58cm
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Answer:
D=12㎝⇒r= 6cm
θ /360° ×2πr+2r=58㎝⇒ θ / 360° ×2× 22 /7×6+2×6=58
198θ /360°×7 +9=58⇒θ
= 7×360° /198 (58−9)
=623.64°
Area= θ / 360° ×πr 2
= 623.64° /360° 22/7 ×6×6
=110.25㎠
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