Find the area of the sector whose arc length is 20 cm and radius is 7 cm
Answers
Answer:
hope it's helpfull bro..
Explanation:
The term glycolysis has originated from the Greek words, glycos for sugar, and lysis for splitting. o The scheme of glycolysis was given by Gustav Embden, Otto Meyerhof, and J. Parnas, and is often referred to as the EMP pathway. o Glycolysis occurs in the cytoplasm of the cell and it is the only process in
anaerobic organisms. o Glycolysis is the process in which glucose, derived from sucrose, undergoes partial oxidation to form two molecules of pyruvic acid. o Glucose and fructose are phosphorylated to give rise to glucose-6- phosphate by the activity of the enzyme hexokinase. o Glucose-6- phosphate isomerises to produce fructose-6-phosphate by
phosphogluco isomerase.
Answer:
Here, length of arc, l=16 cm and r=9 cm
Length of arc, l=
360
o
θ
×2πr
16=
360
o
θ
×2π×9
∴θ=
2π×9
16×360
o
=
π
320
Now, area of sector, A =
360
o
θ
×πr
2
θ
∴A=
360
o
320/π
×π×9×9=72
Hence, the area of sectors is 72cm
2