Find the area of the sector whose length of the arc is 58 cm. and the radius is 10 cm.
Answers
Answer:
- Area of sector is 29 cm²
Explanation:
Given
- Length of arc of sector, l = 58 cm
- Radius of sector, r = 10 cm
To find
- Area of sector =?
Solution
Let, angle subtended by sector at centre be θ
then, using relation
→ θ = l / r
[ where θ is angle subtended on centre (In Radian unit), l is length of arc and r is radius ]
→ θ = 58 / 10
→ θ = 5.8 Rad
converting angle in radian into degree
→ θ = 5.8 Rad
→ θ = 5.8 × 180 / π degrees
Now,
Using formula to calculate area of sector
→ Ar (sector) = (θ/360) × π r²
[ Where θ is angle subtended on centre in degrees & r is radius of sector ]
→ Ar (sector) = [(5.8 × 180 / π)/360] × π × ( 10 )²
→ Ar (sector) = ( 5.8 / 2 ) × 100
→ Ar (sector) = 5.8 × 50
→ Ar (sector) = 29 cm²
Therefore,
- Area of sector is 29 cm².
Question:-
Find the area of the sector whose length of the arc is 58 cm. and the radius is 10 cm.
Solution:-
Here, length of the arc , = 58 cm and r = 10cm
➭ Length of arc , 1 = θ/360° × 2πr
➭ 58 = θ/360 × 2π × 10
∴ θ = 58 × 360° = 1044/π
2π × 10
➭ Now, the area of sector , A = θ/360° × πr²θ
∴ A = 1,044/π × π × 10 × 10 = 275
360