Question

find the area of the sector whose radius is 14 cm and making an angle of 60° at the center​

Answer 1

$60 \div 360 \times 22 \div 7 \times 14 \times 14 \\ = 308 \div 3 \\ = 102.6cm {?}^{2}$

Answer 2

Answer:

102.573 sq.cm

Step-by-step explanation:

Radius = 14 cm

$\theta = 60 ^{\circ}$

Area of sector = $\frac{\theta}{360} \times \pi r^2$

Substitute the value sin the formula.

Area of sector = $\frac{60}{360} \times 3.14 \times  (14)^2$

                      = $\frac{1}{6} \times 3.14 \times  (14)^2$

                      = $102.573 cm^2$

Thus the area of sector is 102.573 sq.cm