find the area of the segment AYB showing in the adjacent figure. if radius of the circle is 21cm and angle AOB=120° ( USE π=22/7 AND √3=1.732 )
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Given angle of arc = 120 degrees
radius of circle = 21 cm
Area of circle = π*r^2
=3.14*21*21
=1386 cm2
Area of Arc= (angle of arc/ 360)*area of circle
= (120 /360)*1386
=1386/3
=462 cm2
Area of triangle = a*b*sinx / 2
=21*21*sin(120) /2
=190.96 cm2
Area of segment = area of arc - area of triangle
=462 - 190.96
=271.04 cm2
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