Question

Find the area of the segment cut off from the parabola x^2
+ 8y by the line x-2y+8=0​

Answer 1

Answer:

x  

2

=8y and x−2y+8=0

x  

2

=4(x+8)

x  

2

−4x−32=0

x=−4;x=8

area is

−4

∫

​  

 

8

​  

[(  

2

x+8

​  

)−  

8

x  

2

 

​  

]dx

−4

∫

​  

 

8

​  

(x/2+4−x  

2

/8)dx=  

4

x  

2

 

​  

∣  

−4

8

​  

+4x∣  

−4

8

​  

−  

24

x  

3

 

​  

∣  

−4

8

​  

 

12+48−24

=36squnits

Step-by-step explanation: