Question

find the area of the segment of a circle given that angle of the sctor is 60° and the radius of the circle is 21 cm​

Answer 1

Answer:

Sorry not know the answer

Answer 2

Explanation:

Area of segment = Area of sector OAPB−ar △OAB

Area of sector =

360

0

θ

×πr

2

=

360

0

60

0

×

7

22

×21×21=231cm

2

for, area of △OAB, draw OM⊥AB, which bisect the ∠O & AB.

∴ △ OAM angle are 30

0

−60

0

−90

0

. Hence the ratio of side is

2

1

:

2

3

:1(by sine rule)

Now, OA=21, ∴AM=

2

21

=10.5m,OM=

2

3

×21=10.5

3

cm

Hence, ar △OAB=2×ar△OAM=2×

2

1

×10.5×10.5

3

=190.73cm

2

∴ Required area =231−190.73=40.27 cm

2

solution