find the area of the shaded design in figure, where ABCD is a square of side 10cm and semicircles are drawn witb each side of the square as diameter. (use π=3.14)
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⎟⎟ ✪✪ QUESTION ✪✪⎟⎟
Fɪɴᴅ ᴛʜᴇ ᴀʀᴇᴀ ᴏғ ᴛʜᴇ sʜᴀᴅᴇᴅ ᴅᴇsɪɢɴ ɪɴ Fɪɢᴜʀᴇ, ᴡʜᴇʀᴇ ABCD ɪs ᴀ sqᴜᴀʀᴇ ᴏf sɪᴅᴇ 10ᴄᴍ ᴀɴᴅ sᴇᴍɪᴄɪʀᴄʟᴇs ᴀʀᴇ ᴅʀᴀᴡɴ ᴡɪᴛʜ ᴇᴀᴄʜ sɪᴅᴇ ᴏf ᴛʜᴇ sϙᴜᴀʀᴇ ᴀs ᴅɪᴀᴍᴇᴛᴇʀ.
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⎟⎟ ✪✪ ANSWER ✪✪⎟⎟
★ Lᴇᴛ ᴜs ᴍᴀʀᴋ ᴛʜᴇ ғᴏᴜʀ ᴜɴsʜᴀᴅᴇᴅ ʀᴇɢɪᴏɴs ᴀs 1, 2, 3 ᴀɴᴅ 4. ★
ᴀʀᴇᴀ ᴏғ 1 + ᴀʀᴇᴀ ᴏғ 3 = ᴀʀᴇᴀ ᴏғ ᴀʙᴄᴅ - ᴀʀᴇᴀs ᴏғ ᴛᴡᴏ sᴇᴍɪᴄɪʀᴄʟᴇs ᴡɪᴛʜ ʀᴀᴅɪᴜs 5 ᴄᴍ .
⇒ 10 × 10 - 2 × 1/2 × π × 5^2
⇒ 100 - 3.14 × 25
⇒ 100 - 78.5 = 21.5 cm^2
sɪᴍɪʟᴀʀʟʏ, ᴀʀᴇᴀ ᴏғ 2 + ᴀʀᴇᴀ ᴏғ 4 = 21.5 ᴄᴍ^2
sᴏ, ᴀʀᴇᴀ ᴏғ ᴛʜᴇ sʜᴀᴅᴇᴅ ʀᴇɢɪᴏɴ
= ᴀʀᴇᴀ ᴏғ ABCD - ᴀʀᴇᴀ ᴏғ ᴜɴsʜᴀᴅᴇᴅ ʀᴇɢɪᴏɴ
= 100 - 2 × 21.5
= 100 - 43
= 57
.°. ᴛʜᴇ ᴀʀᴇᴀ ᴏғ ᴛʜᴇ sʜᴀᴅᴇᴅ ʀᴇɢɪᴏɴ = 57 cm^2
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