Question

Find the area of the shaded portion 30m45m
25m
50m
50m
60 m​

Answer 1

Answer:

Answer

Length of rectangle ABCD =50 m

Breadth of rectangle ABCD =5 m

Area of rectangle ABCD =L×B

=50×5

=250 m

2

Length of rectangle EFGH =35 m

Breadth of rectangle EFGH =5 m

Area of rectangle EFGH =35×5

=175 m

2

Length of rectangle ILKL =5 m

Breadth of rectangle IJKL =5 m

Area of rectangle IJKL =35×5

=175 m

2

Now,

Area of shaded portion = (Area of ABCD + Area of EFGH) − Area of IJKL

=(250+175)−25

=425−25

=400 m

2

Hence area of shaded portion is 400 m

Step-by-step explanation:

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